2. Our calculation is similar to that shown in Sample Problem 43-1. We setK=5.30 MeV =U=(1/4πε0)(qαqCu/rmin) and solve for the closest separation,rmin:rmin=qαqCu40K=kqαqCu40K=(2e)(29)(1.60×10−19C)(8.99×109V·m/C)5.30×106eV=1.58×10−14m=15.8fm.We note that the factor of
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.