p43_014 - . 81% for 31 P, 0 . 83% for 81 Br, . 81% for 120...

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14. (a) The mass number A is the number of nucleons in an atomic nucleus. Since m p m n the mass of the nucleus is approximately Am p . Also, the mass of the electrons is negligible since it is much less than that of the nucleus. So M Am p . (b) For 1 H, the approximate formula gives M Am p = (1)(1 . 007276 u) = 1 . 007276 u. The actual mass is (see Table 47-1) 1 . 007825 u. The percent error committed is then δ = (1 . 007825 u 1 . 007276 u) / 1 . 007825 u = 0 . 054%. Similarly, δ =0 . 50% for 7 Li, 0
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Unformatted text preview: . 81% for 31 P, 0 . 83% for 81 Br, . 81% for 120 Sn, 0 . 78% for 157 Gd, 0 . 74% for 197 Au, 0 . 72% for 272 Ac, and 0 . 71% for 239 Pu. (c) No. In a typical nucleus the binding energy per nucleon is several MeV, which is a bit less than 1% of the nucleon mass times c 2 . This is comparable with the percent error calculated in part (b), so we need to use a more accurate method to calculate the nuclear mass....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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