p43_015 - 15. (a) The de Broglie wavelength is given by =...

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15. (a) The de Broglie wavelength is given by λ = h/p ,where p is the magnitude of the momentum. The kinetic energy K and momentum are related by Eq. 38-51, which yields pc = p K 2 +2 Kmc 2 = p (200 MeV) 2 + 2(200 MeV)(0 . 511 MeV) = 200 . 5MeV . Thus, λ = hc pc = 1240 eV · nm 200 . 5 × 10 6 eV =6 . 18 × 10 6 nm = 6 . 18 fm . (b) The diameter of a copper nucleus, for example, is about 8
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