p43_017 - p โˆ† p h โˆ† x h/r we get E = p 2 2 m hc 2 2 mc...

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17. We note that hc = 1240 MeV · fm (see problem 3 of Chapter 39), and that the classical kinetic energy 1 2 mv 2 can be written directly in terms of the classical momentum p = mv (see below). Letting
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Unformatted text preview: p ' โˆ† p ' h/ โˆ† x ' h/r , we get E = p 2 2 m ' ( hc ) 2 2( mc 2 ) r 2 = (1240 MeV ยท fm) 2 2(938 MeV)[(1 . 2 fm)(100) 1 / 3 ] 2 ' 30 MeV ....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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