p43_021 - 24 . 312 = (23 . 98504)(0 . 7899) + 24 . 98584 f...

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21. Let f 24 be the abundance of 24 Mg, let f 25 be the abundance of 25 Mg, and let f 26 be the abundance of 26 Mg. Then, the entry in the periodic table for Mg is 24 . 312 = 23 . 98504 f 24 +24 . 98584 f 25 +25 . 98259 f 26 . Since there are only three isotopes, f 24 + f 25 + f 26 =1 . Weso lvefor f 25 and f 26 . The second equation gives f 26 =1 f 24 f 25 . We substitute this expression and f 24 =0
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Unformatted text preview: 24 . 312 = (23 . 98504)(0 . 7899) + 24 . 98584 f 25 + 25 . 98259 (25 . 98259)(0 . 7899) 25 . 98259 f 25 . The solution is f 25 = 0 . 09303. Then, f 26 = 1 . 7899 . 09303 = 0 . 1171. 78 . 99% of naturally occurring magnesium is 24 Mg, 9 . 30% is 25 Mg, and 11 . 71% is 26 Mg....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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