Unformatted text preview: . 008665 u − 1 . 000000 u)(931 . 5 MeV / u) = +8 . 07 MeV . (c) Appealing again to Table 431, we obtain, for 120 Sn, ∆ = (119 . 902199 u − 120 . 000000 u)(931 . 5 MeV / u) = − 91 . 10 MeV ....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics, Mass, Neutron

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