Unformatted text preview: E = ( Z H + N n )+( Z + N A ) c 2 = Z H + N n , where A = Z + N is used. or 197 79 Au, Z = 79 and N = 197 79 = 118. Hence, E be = (79)(7 . 29 MeV) + (118)(8 . 07 MeV) ( 31 . 2 MeV) = 1560 MeV . This means the binding energy per nucleon is E ben = (1560 MeV) / 197 = 7 . 92 MeV....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics, Energy, Mass, Neutron

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