p43_025

# p43_025 - E = Z H N n Z N A c 2 = Z H N n where A = Z N is...

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25. If a nucleus contains Z protons and N neutrons, its binding energy is ∆ E be =( Zm H + Nm n m ) c 2 , where m H is the mass of a hydrogen atom, m n is the mass of a neutron, and m is the mass of the atom containing the nucleus of interest. If the masses are given in atomic mass units, then mass excesses are deFned by ∆ H =( m H 1) c 2 ,∆ n =( m n 1) c 2 ,and∆=( m A ) c 2 . This means m H c 2 =∆ H + c 2 , m n c 2 =∆ n + c 2 ,and mc 2 =∆+ Ac 2 .Thu
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Unformatted text preview: E = ( Z H + N n )+( Z + N A ) c 2 = Z H + N n , where A = Z + N is used. or 197 79 Au, Z = 79 and N = 197 79 = 118. Hence, E be = (79)(7 . 29 MeV) + (118)(8 . 07 MeV) ( 31 . 2 MeV) = 1560 MeV . This means the binding energy per nucleon is E ben = (1560 MeV) / 197 = 7 . 92 MeV....
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## This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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