p43_038 - the amount of helium gas produced (assuming the...

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38. We have one alpha particle (helium nucleus) produced for every plutonium nucleus that decays. To Fnd the number that have decayed, we use Eq. 43-14, Eq. 43-17, and adapt Eq. 43-20: N 0 N = N 0 ³ 1 e t ln 2 /T 1 / 2 ´ = N A 12 . 0g / mol 239 g / mol ³ 1 e 20000 ln 2 / 24100 ´ where N A is the Avogadro constant. This yields 1 . 32 × 10 22 alpha particles produced. In terms of
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Unformatted text preview: the amount of helium gas produced (assuming the α particles slow down and capture the appropriate number of electrons), this corresponds to m He = µ 1 . 32 × 10 22 6 . 02 × 10 23 / mol ¶ (4 . 0 g / mol) = 87 . 9 × 10 − 3 g ....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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