44.(a) The rate at which Radium-226 is decaying isR=λN=µln 2T1/2¶µMm¶=(ln 2)(1.00 mg)(6.02×1023/mol)(1600 y)(3.15×107s/y)(226 g/mol)=3.66×107s−1.(b) Since 1600 yÀ3.82 d the time required istÀ3.82 d.(c) It is decaying at the same rate as it is produced, orR.66×107s−1.(d) From
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.