p43_047 - 47. The fraction of undecayed nuclei remaining...

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47. The fraction of undecayed nuclei remaining after time t is given by N N 0 = e λt = e (ln 2) t/T 1 / 2 where λ is the disintegration constant and T 1 / 2 (= (ln 2) ) is the half-life. The time for half the original 238 U nuclei to decay is 4 . 5 × 10 9 y. For 244 Pu at that time, (ln 2) t T 1 / 2 = (ln 2)(4 . 5 × 10 9 y) 8 . 2 × 10 7 y =38 . 0 and N N 0 = e 38 . 0 =3 . 1 × 10 17 . For 248 Cm at that time, (ln 2) t T 1 / 2 = (ln 2)(4 . 5 × 10 9 y) 3 . 4 × 10
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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