p43_048 - 48. (a) The nuclear reaction is written as E1 U...

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48. (a) The nuclear reaction is written as 238 U 234 Th + 4 He . The energy released is E 1 =( m U m He m Th ) c 2 = (238 . 05079 u 4 . 00260 u 234 . 04363 u)(931 . 5MeV / u) =4 . 25 MeV . (b) The reaction series consists of 238 U 237 U+ n, followed by 237 U 236 Pa + p 236 235 Pa + n 235 234 Th + p The net energy released is then E 2 m 238 U m 237 U m n ) c 2 +( m 237 U m 236 Pa m p ) c 2 +( m 236 Pa m 235 Pa m n ) c 2 m 235 Pa m 234 Th m p ) c 2 m 238 U 2 m n 2 m p m 234 Th ) c 2 = [238
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