p43_052 - A = 4 n + k − 4 m = 4( n − m ) + k , still in...

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52. (a) The mass number A of a radionuclide changes by 4 in an α decay and is unchanged in a β decay. If the mass numbers of two radionuclides are given by 4 n + k and 4 n 0 + k (where k =0 , 1 , 2 , 3), then the heavier one can decay into the lighter one by a series of α (and β ) decays, as their mass numbers diFer by only an integer times 4. If A =4 n + k ,thena f te r α -decaying for
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Unformatted text preview: A = 4 n + k − 4 m = 4( n − m ) + k , still in the same chain. (b) 235 = 58 × 4 + 3 = 4 n 1 + 3 , 236 = 59 × 4 = 4 n 2 , 238 = 59 × 4 + 2 = 4 n 2 + 2 , 239 = 59 × 4 + 3 = 4 n 2 + 3 , 240 = 60 × 4 = 4 n 3 , 245 = 61 × 4 + 1 = 4 n 4 + 1 , 246 = 61 × 4 + 2 = 4 n 4 + 2 , 249 = 62 × 4 + 1 = 4 n 5 + 1 , 253 = 63 × 4 + 1 = 4 n 6 + 1....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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