p43_059

# p43_059 - corresponding to two electron masses From Eq...

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59. (a) Since the positron has the same mass as an electron, and the neutrino has negligible mass, then mc 2 =( m B + m e m C ) c 2 . Now, since Carbon has 6 electrons (see Appendix F and/or G) and Boron has 5 electrons, we can add and subtract 6 m e to the above expression and obtain mc 2 =( m B +7 m e m C 6 m e ) c 2 =( m B +2 m e m C ) c 2 . We note that our fnal expression ±or ∆ mc 2 involves the atomic masses, as well an “extra” term
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Unformatted text preview: corresponding to two electron masses. From Eq. 38-47 and Table 38-3, we obtain Q = ( m C − m B − 2 m e ) c 2 = ( m C − m B ) c 2 − 2(0 . 511 MeV) . (b) The disintegration energy ±or the positron decay o± Carbon-11 is Q = (11 . 011434 u − 11 . 009305 u)(931 . 5 MeV / u) − 1 . 022 MeV = 0 . 961 MeV ....
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## This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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