Unformatted text preview: atoms was N U = N U + N Pb = 1 . 06 Ã— 10 19 + 6 . 24 Ã— 10 18 = 1 . 68 Ã— 10 19 . (c) We use N U = N U e âˆ’ Î»t where Î» is the disintegration constant for the decay. It is related to the halflife T 1 / 2 by Î» = (ln 2) /T 1 / 2 . Thus t = âˆ’ 1 Î» ln Âµ N U N U Â¶ = âˆ’ T 1 / 2 ln 2 ln Âµ N U N U Â¶ = âˆ’ 4 . 47 Ã— 10 9 y ln 2 ln Âµ 1 . 06 Ã— 10 19 1 . 68 Ã— 10 19 Â¶ = 2 . 97 Ã— 10 9 y ....
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 Fall '08
 SPRUNGER
 Physics, Mass

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