p43_071 - 71. (a) Adapting Eq. 43-20, we nd N0 = (2.5 103...

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71. (a) Adapting Eq. 43-20, we fnd N 0 = (2 . 5 × 10 3 g)(6 . 02 × 10 23 / mol) 239 g / mol =6 . 3 × 10 18 . (b) From Eq. 43-14 and Eq. 43-17, | N | = N 0 h 1 e t ln 2 /T 1 / 2 i =( 6 . 3 × 10 18 ) h 1 e (12 h) ln 2 / (24 , 100 y)(8760 h / y) i =2 . 5 × 10 11 . (c) The energy absorbed by the body is (0 . 95) E α | N | =(0 . 95) (5 . 2MeV) ( 2 . 5 × 10 11 )( 1 . 6 × 10 13 J / MeV
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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