p43_082 - Z f = Z i + 3∆ Z α + 2∆ Z β and A f = A i +...

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82. The lines that lead toward the lower left are alpha decays, involving an atomic number change of Z α = 2 and a mass number change of ∆ A α = 4. The short horizontal lines toward the right are beta decays (involving electrons, not positrons) in which case A stays the same but the change in atomic number is ∆ Z β = +1. Fig. 43-16 shows three alpha decays and two beta decays; thus,
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Unformatted text preview: Z f = Z i + 3∆ Z α + 2∆ Z β and A f = A i + 3∆ A α . Referring to Appendix F or G, we ±nd Z i = 93 for Neptunium, so Z f = 93 + 3( − 2) + 2(1) = 89, which indicates the element Actinium. We are given A i = 237, so A f = 237 + 3( − 4) = 225 . Therefore, the ±nal isotope is 225 Ac....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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