p43_083 - ln µ N K N K N Ar N Ca = − λt ln µ 1 1 1 8...

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83. We note that every Calcium-40 atom and Krypton-40 atom found now in the sample was once one of the original number of Potassium atoms. Thus, using Eq. 43-13 and Eq. 43-17, we Fnd
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Unformatted text preview: ln µ N K N K + N Ar + N Ca ¶ = − λt ln µ 1 1 + 1 + 8 . 54 ¶ = − ln 2 T 1 / 2 t which (with T 1 / 2 = 1 . 26 × 10 9 y) yields t = 4 . 3 × 10 9 y....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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