p43_083 - ln N K N K + N Ar + N Ca = t ln 1 1 + 1 + 8 . 54...

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83. We note that every Calcium-40 atom and Krypton-40 atom found now in the sample was once one of the original number of Potassium atoms. Thus, using Eq. 43-13 and Eq. 43-17, we Fnd
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Unformatted text preview: ln N K N K + N Ar + N Ca = t ln 1 1 + 1 + 8 . 54 = ln 2 T 1 / 2 t which (with T 1 / 2 = 1 . 26 10 9 y) yields t = 4 . 3 10 9 y....
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