p43_084 - 2 Liters breath 1 m 3 1000 L 40 breaths min (2880...

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84. We note that 3 . 82 days is 330048 s, and that a becquerel is a disintegration per second (see § 43-3). From Eq. 34-19, we have N V = R V T 1 / 2 ln 2 = µ 1 . 55 × 10 5 Bq m 3 330048 s ln 2 =7 . 4 × 10 10 atoms m 3 where we have divided by volume V . We estimate V (the volume breathed in 48 h = 2880 min) as follows:
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Unformatted text preview: 2 Liters breath 1 m 3 1000 L 40 breaths min (2880 min) which yields V 200 m 3 . Thus, the order of magnitude of N is N V ( V ) 7 10 10 atoms m 3 ( 200 m 3 ) 10 13 atoms ....
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