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Unformatted text preview: 86. Form Appendix F and/or G, we ﬁnd Z = 107 for Bohrium, so this isotope has N = A − Z = 262 − 107 =
155 neutrons. Thus,
∆Eben = (ZmH + N mn − mBh ) c2
((107)(1.007825 u) + (155)(1.008665 u) − 262.1231 u) (931.5 MeV/u)
=
A
262 which yields 7.3 MeV per nucleon. ...
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics, Neutron

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