p43_088 - 88 Adapting Eq 43-20 we have NKr = 20 109 g 92...

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88. Adapting Eq. 43-20, we have N Kr = M sam M Kr N A = µ 20 × 10 9 g 92 g / mol ( 6 . 02 × 10 23 atoms / mol ) =1 . 3 × 10 14 atoms . Consequently, Eq. 43-19 leads to
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