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Unformatted text preview: 8. (a) Using Eq. 4319 and adapting Eq. 4320 to this sample, the number of ﬁssionevents per second is (b) Since R ∝ 1
T1/2 = N ln 2
Msam NA ln 2
=
T1/2 ﬁssion
MU T1/2 ﬁssion = Rﬁssion (1.0 g)(6.02 × 1023 /mol) ln 2
= 16 ﬁssions/day .
(235 g/mol)(3.0 × 1017 y)(365 d/y) (see Eq. 4319), the ratio of rates is
Rα
Rﬁssion = T1/2 ﬁssion
3.0 × 1017 y
=
= 4.3 × 108 .
T1/2 α
7.0 × 108 y ...
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics

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