Unformatted text preview: momentum vector: K = 1 2 mv 2 = p 2 2 m which implies that K Nd = ( m Ge /m Nd ) K Ge . Thus, the energy equation becomes Q = K Ge + M Ge M Nd K Ge = M Nd + M Ge M Nd K Ge and K Ge = M Nd M Nd + M Ge Q = 153 u 153 u + 83 u (170 MeV) = 110 MeV . Similarly, K Nd = M Ge M Nd + M Ge Q = 83 u 153 u + 83 u (170 MeV) = 60 MeV . (c) The initial speed of the germanium nucleus is v Ge = r 2 K Ge M Ge = s 2(110 × 10 6 eV)(1 . 60 × 10 − 19 J / eV) (83 u)(1 . 661 × 10 − 27 kg / u) = 1 . 60 × 10 7 m / s . The initial speed of the neodymium nucleus is v Nd = r 2 K Nd M Nd = s 2(60 × 10 6 eV)(1 . 60 × 10 − 19 J / eV) (153 u)(1 . 661 × 10 − 27 kg / u) = 8 . 69 × 10 6 m / s ....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics, Charge, Mass

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