p44_014 - 14. (a) The surface area a of a nucleus is given...

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14. (a) The surface area a of a nucleus is given by a ' 4 πR 2 ' 4 π [ R 0 A 1 / 3 ] 2 A 2 / 3 . Thus, the fractional change in surface area is a a i = a f a i a i = (140) 2 / 3 +(96) 2 / 3 (236) 2 / 3 1=+0 . 25 . (b) Since V R 3 ( A 1 / 3 ) 3 = A ,wehave V V = V f V i 1= 140 + 96 236 1=0 . (c) The fractional change in potential energy is
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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