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19. If
R
is the decay rate then the power output is
P
=
RQ
,where
Q
is the energy produced by each alpha
decay. Now
R
=
λN
=
N
ln 2
/T
1
/
2
,where
λ
is the disintegration constant and
T
1
/
2
is the halflife. The
relationship
λ
=(
ln2)
/T
1
/
2
is used. If
M
is the total mass of material and
m
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Unformatted text preview: 238 Pu nucleus, then N = M m = 1 . 00 kg (238 u)(1 . 661 × 10 − 27 kg / u) = 2 . 53 × 10 24 . Thus, P = NQ ln 2 T 1 / 2 = (2 . 53 × 10 24 )(5 . 50 × 10 6 eV)(1 . 60 × 10 − 19 J / eV)(ln 2) (87 . 7 y)(3 . 156 × 10 7 s / y) = 558 W ....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics, Energy, Power

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