Unformatted text preview: 20. (a) We solve Qeï¬€ from P = RQeï¬€ :
Qeï¬€ =
=
= (b) The amount of 90 mP T1/2
P
P
=
=
R
NÎ»
M ln 2
(90.0 u)(1.66 Ã— 10âˆ’27 kg/u)(0.93 W)(29 y)(3.15 Ã— 107 s/y)
(1.00 Ã— 10âˆ’3 kg)(ln 2)(1.60 Ã— 10âˆ’13 J/MeV)
1.2 MeV . Sr needed is
M= 150 W
= 3.2 kg .
(0.050)(0.93 W/g) ...
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics

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