p44_024 - N = Pt gen Q =(500 × 10 6 W(1 × 10 − 3 s 3 2...

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24. We recall Eq. 44-6: Q 200 MeV = 3 . 2 × 10 11 J. It is important to bear in mind that Watts multiplied by seconds give Joules. From E = Pt gen = NQ we get the number of free neutrons:
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Unformatted text preview: N = Pt gen Q = (500 × 10 6 W)(1 . × 10 − 3 s) 3 . 2 × 10 − 11 J = 1 . 6 × 10 16 ....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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