p44_029 - 29(a Pavg =(15 109 W y(200 000 y = 7.5 104 W = 75...

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29. (a) P avg =(15 × 10 9 W · y) / (200 , 000 y) = 7 . 5 × 10 4 W=75kW . (b) Using the result of Eq. 44-6, we obtain M = m U E total Q = (235 u)(1 . 66 × 10 27 kg / u)(15
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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