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Unformatted text preview: r = N 235 , /N 238 , (= 0 . 030). We solve for t : t = 1 235 238 ln r r . Now we use 235 = (ln 2) /T 1 / 2 235 and 238 = (ln 2) /T 1 / 2 238 to obtain t = T 1 / 2 235 T 1 / 2 238 ( T 1 / 2 238 T 1 / 2 235 ) ln 2 ln r r = (7 . 10 8 y)(4 . 5 10 9 y) (4 . 5 10 9 y 7 . 10 8 y) ln 2 ln . 0072 . 030 = 1 . 71 10 9 y ....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics

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