p44_036 - r = 3 2 (1 . 6 10 19 C) 2 16 (8 . 85 10 12 F /...

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36. Our calculation is very similar to that in Sample Problem 44-4 except that we are now using R appropriate to two Lithium-7 nuclei coming into “contact,” as opposed to the R =1 . 0 fm value used in the Sample Problem. If we use R = r = r 0 A 1 / 3 =(1 . 2fm) 3 7=2 . 3fm and q = Ze =3 e , then our K is given by (see Sample Problem 44-4) K = Z 2 e 2 16
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Unformatted text preview: r = 3 2 (1 . 6 10 19 C) 2 16 (8 . 85 10 12 F / m)(2 . 3 10 15 m) which yields 2 . 3 10 13 J = 1 . 4 MeV. We interpret this as the answer to the problem, though the term Coulomb barrier height as used here may be open to other interpretations....
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