p44_039 - M He contains the mass of six electrons and so...

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39. If M He is the mass of an atom of helium and M C is the mass of an atom of carbon, then the energy released in a single fusion event is Q =[3 M He M C ] c 2 =[3(4 . 0026 u) (12 . 0000 u)] (931 . 5MeV / u) = 7 . 27 MeV . Note that 3
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Unformatted text preview: M He contains the mass of six electrons and so does M C . The electron masses cancel and the mass diFerence calculated is the same as the mass diFerence of the nuclei....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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