p44_043 - M = dM/dt ∆ t =(4 33 × 10 9 kg s(4 5 × 10 9...

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43. (a) Let M be the mass of the Sun at time t and E be the energy radiated to that time. Then, the power output is P = dE/dt =( dM/dt ) c 2 ,where E = Mc 2 is used. At the present time, dM dt = P c 2 = 3 . 9 × 10 26 W (2 . 998 × 10 8 m / s) 2 =4 . 33 × 10 9 kg / s . (b) We assume the rate of mass loss remained constant. Then, the total mass loss is ∆
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Unformatted text preview: M = ( dM/dt ) ∆ t = (4 . 33 × 10 9 kg / s)(4 . 5 × 10 9 y)(3 . 156 × 10 7 s / y) = 6 . 15 × 10 26 kg. The fraction lost is ∆ M M + ∆ M = 6 . 15 × 10 26 kg 2 . × 10 30 kg + 6 . 15 × 10 26 kg = 3 . 07 × 10 − 4 ....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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