p44_053

# p44_053 - can occur is N = 4 . 75 × 10 21 / 2 = 2 . 38 ×...

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53. Since 1 . 00 L of water has a mass of 1 . 00 kg, the mass of the heavy water in 1 . 00 L is 0 . 0150 × 10 2 kg = 1 . 50 × 10 4 kg. Since a heavy water molecule contains one oxygen atom, one hydrogen atom and one deuter iumatom ,itsmassis(16 . 0u+1 . 00 u + 2 . 00 u) = 19 . 0u or (19 . 0 u)(1 . 661 × 10 27 kg / u) = 3 . 16 × 10 26 kg. The number of heavy water molecules in a liter of water is (1 . 50 × 10 4 kg) / (3 . 16 × 10 26 kg) = 4 . 75 × 10
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Unformatted text preview: can occur is N = 4 . 75 × 10 21 / 2 = 2 . 38 × 10 21 . Each event releases energy Q = (3 . 27 × 10 6 eV)(1 . 60 × 10 − 19 J / eV) = 5 . 23 × 10 − 13 J. Since all events take place in a day, which is 8 . 64 × 10 4 s, the power output is P = NQ t = (2 . 38 × 10 21 )(5 . 23 × 10 − 13 J) 8 . 64 × 10 4 s = 1 . 44 × 10 4 W = 14 . 4 kW ....
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## This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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