p45_009 - E π = p ( p π c ) 2 + ( m π c 2 ) 2 = p (358 ....

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9. Table 45-4 gives the rest energy of each pion as 139 . 6 MeV. The magnitude of the momentum of each pion is p π = (358 . 3MeV) /c . We use the relativistic relationship between energy and momentum (Eq. 38-52) to Fnd the total energy of each pion:
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Unformatted text preview: E π = p ( p π c ) 2 + ( m π c 2 ) 2 = p (358 . 3 MeV) 2 + (139 . 6 MeV) 2 = 384 . 5 MeV . Conservation of energy yields m ρ c 2 = 2 E π = 2(384 . 5 MeV) = 769 MeV....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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