Unformatted text preview: 14. (a) Noting that there are two positive pions created (so, in eﬀect, its decay products are doubled), then
we count up the electrons, positrons and neutrinos: 2e+ + e− + 5ν + 4¯.
(b) The ﬁnal products are all leptons, so the baryon number of A+ is zero. Both the pion and rho
meson have integer-valued spins, so A+ is a meson (and a boson).
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
- Fall '08