p45_017

# p45_017 - 17. (a) See the solution to Exercise 13 for the...

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17. (a) See the solution to Exercise 13 for the quantities to be considered, adding strangeness to the list. The lambda has a rest energy of 1115 . 6 MeV, the proton has a rest energy of 938 . 3MeV, and the kaon has a rest energy of 493 . 7 MeV. The rest energy before the decay is less than the total rest energy after, so energy cannot be conserved. Momentum can be conserved. The lambda and proton each have spin ¯ h/ 2 and the kaon has spin zero, so angular momentum can be conserved. The lambda has charge zero, the proton has charge + e , and the kaon has charge e , so charge is conserved. The lambda and proton each have baryon number +1, and the kaon has baryon number zero, so baryon number is conserved. The lambda and kaon each have strangeness 1 and the proton has strangeness zero, so strangeness is conserved. Only energy cannot be conserved. (b) The omega has a rest energy of 1680 MeV, the sigma has a rest energy of 1197 . 3MeV,andthepion has a rest energy of 135 MeV. The rest energy before the decay is greater than the total rest energy
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