p45_021 - − 1 the strangeness of x is 1 We take the...

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21. (a) As far as the conservation laws are concerned, we may cancel a proton from each side of the reaction equation and write the reaction as p Λ 0 + x . Since the proton and the lambda each have a spin angular momentum of ¯ h/ 2, the spin angular momentum of x must be either zero or ¯ h .S i n c et h e proton has charge + e and the lambda is neutral, x must have charge +
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Unformatted text preview: − 1, the strangeness of x is +1. We take the unknown particle to be a spin zero meson with a charge of + e and a strangeness of +1. Look at Table 45-4 to identify it as a K + particle. (b) Similar analysis tells us that x is a spin-1 2 antibaryon ( B = − 1) with charge and strangeness both zero. Inspection of Table 45-3 reveals it is an antineutron. (c) Here x is a spin-0 (or spin-1) meson with charge zero and strangeness − 1. According to Table 45-4, it could be a K particle....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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