22. (a) From Eq. 38-47, Q = − ∆ mc 2 =( m Λ0 − m p − m π − ) c 2 = 1115 . 6MeV − 938 . 3MeV − 139 . 6MeV=37 . 7MeV . (b) We use the formula obtained in problem 11 (where it should be emphasized that E is used to mean the rest energy, not the total energy): K p = 1 2 E Λ h ( E Λ −
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.