p45_041 - 41. (a) We use the relativistic relationship...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
41. (a) We use the relativistic relationship between speed and momentum: p = γmv = mv p 1 ( v/c ) 2 , which we solve for the speed v : v c = s 1 1 ( pc mc 2 ) 2 +1 . For an antiproton mc 2 = 938 . 3MeV and pc =1 . 19 GeV = 1190 MeV, so v = c s 1 1 (1190 MeV / 938 . 3MeV) 2 +1 =0 . 785 c. For the negative pion mc 2 = 193 . 6MeV, and pc is the same. Therefore, v = c s 1 1 (1190 MeV / 193 . 6MeV) 2 +1 =0 . 993 c. (b) See part (a). (c) Since the speed of the antiprotons is about 0 . 78 c but not over 0 . 79 c , an antiproton will trigger C1.
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

Ask a homework question - tutors are online