{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

Homework 1 - soto(rrs946 Homework 1 Spurlock(41003 This...

Info icon This preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
soto (rrs946) – Homework 1 – Spurlock – (41003) 1 This print-out should have 30 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 (part 1 of 2) 10.0 points Use linear combinations to solve the system braceleftbigg 2 x - y = - 2 - 5 x + y = 68 The value of x is 002 (part 2 of 2) 10.0 points The value of y is 003 (part 1 of 2) 10.0 points In a certain right triangle, the two sides that are perpendicular to each other are 6 . 7 m and 6 . 5 m long. What is the length of the third side? Answer in units of m. 004 (part 2 of 2) 10.0 points What is the tangent of the angle for which 6 . 7 m is the opposite side? 005 10.0 points Solve 3 x 2 - 20 x + 4 = 0 What is the smaller answer? Answer - 1000 if there is no real value of x that solves this equation. 006 10.0 points Solve 60 x 36 for x . 007 10.0 points Solve 43 18 r for r . 008 10.0 points From an h = 67 feet observation tower on the coast, a Coast Guard officer sights a boat in difficulty. The angle of depression of the boat is θ = 3 .
Image of page 1

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern