hw4 - CSCE 464 Wireless and Mobile Systems Fall 2011...

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CSCE 464 Wireless and Mobile Systems Fall 2011 Homework 4 (50 points) Problem 1 (10 points) This problem will help you understand why you cannot achieve the physical layer rate at the medium access layer in 802.11 and will give you an idea that medium access layer throughput is roughly half of the physical layer data rate. 802.11 physical layer transmission rate = 54Mbps MAC layer data payload = 1452 bytes MAC header = 28 bytes ACK Frame Size = 14 bytes RTS Frame Size = 20 bytes CTS Frame Size = 14 bytes SIFS Time = 16 μ s DIFS Time = 34 μ s Define MAC layer throughput as the number of bits sent by the MAC layer in a given period of time. 1. Assuming that there are two stations exchanging data using 802.11 DCF but without using RTS/CTS transaction, what is MAC layer throughput? 2. What is the throughput when RTS/CTS is used? Problem 2 (10 points) The figure below shows 7 nodes named A, B, C, D and E. The number shown on links connecting various nodes are the path gains between the correspond-
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hw4 - CSCE 464 Wireless and Mobile Systems Fall 2011...

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