This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: Winter 2011 • Math 67 • Linear Algebra Homework 6 Problems 5.9, 5.14 and 5.19 from Axler. Solution. (5.9) Suppose that T : V → V is a linear map with rank k . If v is an eigenvector with a nonzero eigenvector λ then T ( v/λ ) = v . This implies that v is in the range of T . There are at most k distinct nonzero eigenvalues of T , since each such eigenvector is in the range (which is kdimensional), and eigenvectors with distinct eigenvalues are linearly independent. Taking into account that 0 is a possible eigenvalues, one sees that there are at most k + 1 distinct eigenvalues of T . Solution. (5.14) We only need to check that this for p ( z ) = z m . In this case p ( STS 1 ) = ( STS 1 )( STS 1 )( STS 1 ) ... ( STS 1 )( STS 1 ) Rearranging the parenthesis we get the pairs S 1 S cancel, except for the S on the left and the S 1 on the right. We get p ( STS 1 ) = STTT ...TS 1 = ST m S 1 ....
View
Full Document
 Winter '07
 Schilling
 Linear Algebra, Algebra, Eigenvectors, Eigenvalues

Click to edit the document details