Homework 4 Problem 3 SuperPro Designer Crystallization Equilibrium

Homework 4 Problem 3 SuperPro Designer Crystallization Equilibrium

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Unformatted text preview: Homework 4 Problem 3 SuperPro Designer™ Crystallization Equilibrium 30 points possible due Tuesday September 27, 2011 Grader: Alan Problem Statement: The first order equilibrium reaction of A → B has an equilibrium constant, Keq, of 0.10. The reaction enthalpy is assumed to be 0 kcal/kg. B is the precipitate formed when water is added to component A. This reaction occurs in a simple reactor at STP. Determine how much of component B is formed after 15 minutes if 100 kg of component A is mixed with 1,000 kg of water. Method of Solution: Use the SuperPro Designer to simulate the batch process. Solution: 1) Open the SuperPro DesignerTM program and start a new case. 2) Select “Batch Mode” and click OK. 3) To register the process components select Tasks → Pure Component → Register, Edit/View Properties… from the toolbar. 4) Components that are not found in the SuperPro Designer databank must be added into the simulation by the user and are therefore considered user define components. To enter a user defined component, click the Add a New Component button , which is in the upper right hand corner of the Registered Pure Components box. Do so now to add the components for this simulation. 5) The New Component Definition window will appear. Type in the component name A, which will automatically fill in the subsequent naming regions of this window, click OK to close. 6) Also, add components B and water. 7) Click OK to close the Register/Edit Pure Components window. Save the case. 8) Add a reactor to the PFD from the Unit Procedures Batch Vessel Procedure in a Reactor menu on the toolbar. 9) Connect a feed and product stream to the reactor by clicking the Connect Mode button shown below: . The process flow diagram should now look like the one 10) Change the name of stream S‐101 to Feed by clicking Edit → Stream Options → Edit Tag Name… Also, change the name of stream S‐102 to Product. 11) Double click on the Feed stream. Add component A and water to the feed with flowrates of 100 kg/batch and 1,000 kg/batch, respectively. The feed stream enters at a temperature of 25oC, and a pressure of 1.013 bar. 12) Right click the reactor and select Add/Remove Operations… 13) Add the operation charge, react (equilibrium) and transfer‐out. Click OK to close. 14) Charge‐1: Feed a. Right click the reactor and select Charge‐1 from the Operation Data. b. Under the Operating Conditions tab, charge using the Feed stream with a mass of 1,100 kg, no setup time and a process time of 15 minutes. c. Click the next button to go to the next operation. 15) REACT‐1 a. Under the Oper.Cond’s tab enter the reaction time as 15 minutes, which was given in the problem statement. b. Open the reactions tab and add an equilibrium reaction to the case by clicking the button. i. The reaction for this case based on mass coefficients is: A → B Click OK to save the changes and close the window. ii. This reaction has an enthalpy of 0 kcal/kg at a reference temperature of 25oC. On the reactions tab, uncheck the Ignore button and select A as the reference component. iii. Click the button to open the equilibrium data window. this reaction is 1st order in A. Enter 1 as the exponent for A. The equilibrium constant, Keq, is 0.10. iv. The reaction is fully defined, click the next button to move onto the next step. 16) Transfer‐Out‐1: Product Select Product as the transfer out stream without a setup time and a process time of 15 minutes. 17) The process has been fully defined, click OK to close the Operation Data window and save the file. 18) Click Task → Solve M&E Balances or the button from the toolbar to run the process. 19) Open the Product product stream to check the simulation results. You should have the following compositions and flowrates. 20) Save the file before moving onto the next step. 21) Select Reports → Materials & Streams (SR) from the toolbar to view and print a full report of the process results. Results/Considerations: After 15 minutes this reaction is 98% complete and has produced 98 kg of the precipitate B. After 30 minutes we see the same results for each component. Therefore, one can conclude that approximately 2% of reactant A will remain in the solution once the reaction is complete. ...
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