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IRWIN 9e 8_33

IRWIN 9e 8_33 - Irwin Basic Engineering Circuit Analysis...

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Unformatted text preview: Irwin, Basic Engineering Circuit Analysis, 9/E 1 3.33 If 115(1) = 211] cos 5: volts, find 11.3{1} in the new-r0115: in Fig. PB.33. Figure P333 SOLUTION: 2L, 2 j5(o-5) : J'2-5_n_ Zr: JC5XU: J‘5-‘l EC : I : i} 10.0. JCSMO'oz) i, : 7. 07 tr HSOJL Chapter 8: AC Steady-State Ana|ysis Problem 8.33 2 Irwin, Basic Engineering Circuit Analysis, 9/E "‘0: szow) 7-07L+w5°+2+j2'5 x70 : 12~CI 41-85°\/ VOW) : I2'q COA(5t +l”875'°)\/ ___________________—— Problem 8.33 Chapter 8: AC Steady-State Analysis ...
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