IRWIN 9e 8_112

# IRWIN 9e 8_112 - |n~in Basic Engineering Circuit Analysis...

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Unformatted text preview: |n~in, Basic Engineering Circuit Analysis, 9/E 8.112 Um: Hanna‘s theorem m ﬁml 1} in the netwurk in Fig. PH] 12. xi)?- A Figure P8112 SOLUTION: 4&A 10 i : 32:1, Kvu lCih JIFi'xH Mic) JrJI 11:0 Chapter 8: AC Steady-State Analysis Problem 8.112 2 Irwin, Basic Engineering Circuit Analysis, 9/E TL": +J'(L1£O°—i5¢)‘l‘ff5¢+jl—fzto ~f. w“ (H1!) "1’1 -l C r—Mffgg =— 94432:“ T, = HLO" A CHJi) i. H: Hi)?“ : 566 L415" kcu 29} + ic = "I: v”: 'J‘j: : ~J'CHLO°~ Tu.) ~12 (wound-r i; -350 ~‘I; +(m' 2) {SC : uqo" OH.) Ii H.401; .1 5-66 1-HT “’1; —l ( H31) T36 : 8046’ ~— 11 : 293 L435" A \l Tgc, 2'33 ALISOA Problem 8.112 Chapter 8: AC Steady-State Analysis Irwin, Basic Engineering Circuit Analysis, 9/E 1f). Chapter 8: AC Steady-State Analysis Problem 8.112 4 Irwin. Basic Engineering Circuit Analysis. 9/E vac : 5'44 446° +(—!~jl)(5’Z—90°) VOL: 5-65 msov 2H : ML: Mi= 2mm it 2-373 /. (45° .. ‘L : ; ( Zqu" )(2-33Lw50):2'5217r6°/\ /o |+2L90 R70 : M’Z‘SZLW‘S“) VD: 2'53 L7"6° V _______________________.__—_————————————— Problem 8.112 Chapter 8: AC Steady-State Analysis ...
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