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IRWIN 9e 8_116

# IRWIN 9e 8_116 - Irwin Basic Engineering Circuit Analysis...

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Unformatted text preview: Irwin, Basic Engineering Circuit Analysis, 9/E 3.115 Find the Thévenin equivalent of the network in Fig. PBJ 16 nt terminals A—B. I A B I Figure PB.11I5 SOLUTION: r l KVL: ui,+i’(~Jl) “270} VA: ICE—03ft Chapter 8: AC Steady-State Analysis Problem 8.116 2 Irwin. Basic Engineering Circuit Analysis, 9/E Hf, ~11 (17—1) = 2(1) '<VL= 2% - Jib?) +l(fL)—ljlff”:o 2(1)+ji(f,'i’;) +1+Ji('f;fr’3)=o (1H4)? + it; *Jli: =0 (27m? -r Jift; =0 (2M) TN T1:- lL’qO’ T, : 0le 4435" A :1: 0-53 ['7 l'57oA '1‘” : f; ‘1'; 30'53L'7l'570‘ (’ILO") :T” : 1-21 4—23‘3°A V : 1-27 Aria-3 °(J’) Problem 8.116 7 Chapter 8: AC Steady-State Analysis InNin, Basic Engineering Circuit Analysis, 91E 3 V : 1,27 L66'7° v N —l I H j; :- i27 Age-7° i Mo" 21H : i-Z'I Lee-7U?— ZH = 0-5 +j'"7 A A 05.0. Jinn. __________________——————— Chapter 8: AC Steady-State Analysis Problem 8.116 ...
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IRWIN 9e 8_116 - Irwin Basic Engineering Circuit Analysis...

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