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IRWIN 9e 8_122

IRWIN 9e 8_122 - Irwin Basic Engineering Circuit Analysis...

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Unformatted text preview: Irwin. Basic Engineering Circuit Analysis, 9/E 3.1:: Use The'veniu’s theorem, in conjunction with MATLAB, to determine In in the netwm'k in Fig. 133.122. Figure H.122 SOLUTION: Chapter 8: AC Steady-State Analysis Problem 8.122 2 . Irwin, Basic Engineering Circuit Analysis, 9/E 'j|(\7,~93) ‘f {71—03 1' “j’V3 —jl \7. iv“; -r (-l J’l v3: \75' : 6LO°V 20, “T13 ”U9: ~ZLO° _J-1V,+(-r+j;)‘\7‘3 = —240" iii/'1 + (“#er UL! : 6L"‘10° V! H MM 63" 2° V V3 2 p674 53~I2°v V 3'074V0‘6°V Problem 8.122 Chapter 8: AC Steady-State Analysis Irwin, Basic Engineering Circuit Analysis, 9/E \7oL = "\73’ 911 1 P6745543" —— 3'01Aw0~6° \TOC : H43 445361" v Chapter 8: AC Steady-State Analysis Problem 8.122 4 . Inivin, Basic Engineering Circuit Analysis, 9/E f0 : K795 : l-Wz—igg.51° 2174+, 1/; 40° + l f0: 0379 A» i53'51°A y: [I ,,/..',- -l+?_5 0;; 0+2] 1-— Elfin-6"] v: invCVYKI Voc : WU” VC3) Io : Vac /(ZTH+ ’) 0A Hmumt y : 20090 ~I'OOOO g—I'OOOO o ~I'0000i —l'OOOO+2'ODOOI' 0 o + l'ODDoi O "I'OOOO~2-Ooot>j I: —2-0000 -2 .0000 Oné‘Ooooi Problem 8.122 Chapter 8: AC Steady-State Analysis Irwin, Basic Engineering Circuit Ana|ysis, 9/E 5 06667 + #66671 Ivoooo +1.33337 2.3333 + 1-0000; VOC : "F333;? ‘0‘ 6667 i u— .— 2TH O'ééfl Io : ~0-2000 — O‘VOOOi _____________________.———————~—— Chapter 8: AC Steady-State Analysis Problem 8.122 ...
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