IRWIN 9e 8_127

IRWIN 9e 8_127 - Irwin, Basic Engineering Circuit Analysis,...

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Unformatted text preview: Irwin, Basic Engineering Circuit Analysis, 9/E 1 3.127 Find 1:. in the. network in Fig. 138.12? using I'i-IATLAB. Figure P342? SOLUTION: Chapter 8: AC Steady-State Analysis Problem 8.127 2 Irwin, Basic Engineering Circuit Analysis. 9/E J'ml +JI(LIAQ°) +95 : Jinn?) ‘ jl "\71 '1 C5 '5 2L”CIO \7pT/3 T 6Lo° ., / (H3)EHIVz’VfiJWH—Hivg:o jIU1+Jivg+(‘I‘JL)\75 :0. Jig; ‘f C"5 : 11-q00- Problem 8.127 Chapter 8: AC Steady-State Analysis llwin, Basic Engineering Circuit Analysis, 9/E 3 \71'V3 : 6LO° —U3 CL, 2 I2Lo° I], : L7 L‘CW'IEOV V1: 2'86L15fl"650\/ v3 : 863117093°V g”: 3.7942i’35°v {75 2 We A 20~Cil°V To : _\/,,\7‘5 : 3'7HL1I'3YDJ'96190'Qz" ) i To: 218 A “ll-63°13; MHTLAQ gomfiw x \ y]; [1-3; ,- —I .- i;i ooi—I-1.‘;Oi00!;Oi—loo,'00"f0] I: [CD/'O}.—~Zi'j6/‘ilj V— n'nv(\/)*I / (Io: V( H)‘ V05) /l Chapter 8: AC Steady-State Analysis Problem 8.127 4 irwin, Basic Engineering Circuit Analysis. 9/E 79 Awswcks: Y 2:. CC)th mm)an 3 I'Oooo ' 3'ooooi 0+ i-Ooooi -i' 0000 O +r'0000i o O O Ov‘i‘ i'Oomi' 0 0 10000 “(0000 O 0 ~' (“0000 COUJhmA H ‘Hnrouggi 5 O + I~ 0000i 0+ I-oOooi O + i'OOOOi doom) v 1.00006 O #0000 O O (-000 O O 1:. O O O I 1000} / 6-0000 l2- 0000 “01900 — P6 800% -252DD +i36ooi »8'52001'r3soo( 3*{200'f136009 13030 f 0'52006 ___________._______————————————-—- , Problem 8.127 Chapter 8: AC Steady-State Analysis Inivin, Basic Engineering Circuit Analysis, 91E Io 1—" 2- i200 +Q'8LIOOI' ' Chapter 8: AC Steady—State Analysis Problem 8.127 ...
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IRWIN 9e 8_127 - Irwin, Basic Engineering Circuit Analysis,...

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