IRWIN 9e 8_FE-2

IRWIN 9e 8_FE-2 - KCL at node 0: 2 2 2 I I x 2 2 1 2 2 1 V...

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Irwin, Basic Engineering Circuit Analysis, 9/E 1 Chapter 8: AC Steady-State Analysis Problem 8.FE-2 SOLUTION: 1 I 1 j 1 V 0 12 x I 2 1 V 2 V text 0 V 2 I x I A 0 2 2 The correct answer is c .
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2 Irwin, Basic Engineering Circuit Analysis, 9/E Problem 8.FE-2 Chapter 8: AC Steady-State Analysis V V 0 12 2 1 1 j V I x 0 2 1 I I I x x 0 1 0 12 1 1 2 1 1 1 V j V j V 0 ) 0 12 ( 1 1 2 1 1 1 j V j V V V j j j V 6 . 3 2 . 1 1 3 ) 0 12 ( 1 1
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Unformatted text preview: KCL at node 0: 2 2 2 I I x 2 2 1 2 2 1 V V j V 2 2 12 1 6 . 3 2 . 1 2 V j j V V 97 . 8 8 . 30...
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IRWIN 9e 8_FE-2 - KCL at node 0: 2 2 2 I I x 2 2 1 2 2 1 V...

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