IRWIN 9e 8_FE-3

# IRWIN 9e 8_FE-3 - Two equations and two unknowns 12 2 8 2 2...

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Irwin, Basic Engineering Circuit Analysis, 9/E 1 Chapter 8: AC Steady-State Analysis Problem 8.FE-3 SOLUTION: V 0 12 1 j 4 2 j 0 2 V 2 2 I 1 I 0 V + - I The correct answer is a . 2 1 I I I 2 1 I I I KVL around the left loop: 0 1 2 2 2 0 12 V I j I 2 0 4 I V 0 12 ) 2 8 ( ) 2 2 ( 2 1 I j I j KVL around the right loop: 2 2 0 4 1 2 2 I I j I j V 0 ) 1 4 ( 2 2 1 I j I j

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2 Irwin, Basic Engineering Circuit Analysis, 9/E Problem 8.FE-3 Chapter 8: AC Steady-State Analysis
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Unformatted text preview: Two equations and two unknowns: 12 ) 2 8 ( ) 2 2 ( 2 1 I j I j ) 1 4 ( 2 2 1 I j I j It follows that: A I 45 24 . 4 1 A I 96 . 30 06 . 2 2 ) 96 . 30 06 . 2 ( 4 V V V 96 . 30 24 . 8...
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IRWIN 9e 8_FE-3 - Two equations and two unknowns 12 2 8 2 2...

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