m233_E3sSP10 - Page 1 Math 233 Exam 3 Name: ID: This exam...

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Unformatted text preview: Page 1 Math 233 Exam 3 Name: ID: This exam has 20 multiple choice questions, worth 5 points each. You are allowed to use a scientific calculator and a 3 5 inch note card. 1. Find R C F , where F ( x, y ) = h y, x 2 i and C goes along the parabola y = x 2 from (0 , 0) to (1 , 1). (a)- 1 (b)- 1 / 2 (c)- 1 / 3 (d) 0 (e) 1 / 4 (f) 1 / 2 (g) 2 / 3 (h) 3 / 4 (i) 5 / 6 (j) 1 (I) The vector field is not conservative ( q x = 2 x , whereas p y = 1 ), so the best approach in this case is to directly compute the curve integral. The curve can be parametrized as C ( t ) = ( t, t 2 ) as t goes from to 1 , and the integral is Z 1 F ( C ( t )) C ( t ) d t = Z 1 t 2 , t 2 h 1 , 2 t i d t = Z 1 t 2 + 2 t 3 d t = t 3 3 + t 4 2 1 = 1 3 + 1 2 = 5 6 . Page 2 Math 233 Exam 3 2. Find R C F , where F ( x, y ) = h ye xy , xe xy i and C goes along the parabola y = x 2 from (0 , 0) to (1 , 1). (a) 0 (b) ln 2 (c) 1 (d) e- 1 2 (e) 2 3 ( e- 1) (f) e- 1 (g) e 2 (h) e 2 2 (i) e 2 (j) e 3 (F) The vector field is conservative (both q x and p y equal e xy + xye xy ), so the FTC can be used. First integrate the vector field to get a potential function: f ( x, y ) = Z ye xy d x = e xy + g ( y ) and f ( x, y ) = Z xe xy d y = e xy + h ( x ) . The above results agree when g ( y ) = 0 and h ( x ) = 0 , making the potential function f ( x, y ) = e xy . [Note: at this point, you can double-check that f = F .] By the FTC, the integral is simply f (1 , 1)- f (0 , 0) = e- 1 . Page 3 Math 233 Exam 3 3. Find R C G , where G ( x, y ) = D- y x 2 + y 2 , x x 2 + y 2 E and C is the path in the picture at the top of this page. (a)- 2 (b)- (c)- ln 2 (d)- 1 / 2 (e) 0 (f) 1 / 2 (g) ln 2 (h) (i) 2 (I) G is the very special vector field, which integrates to 2 for any closed curve going around the origin once counterclockwise. 4. Find R C F , where F ( x, y ) = D x x 2 + y 2 , y x 2 + y 2 E and C is the path in the picture at the top of this page. (a)- 2 (b)- (c)- ln 2 (d)- 1 / 2 (e) 0 (f) 1 / 2 (g) ln 2 (h) (i) 2 (E) This vector field (which can also be written as 1 r 2 X ) is conservative. Since F is conservative and C is a closed curve, the integral is . Page 4 Math 233 Exam 3 5. Find R C G , where G ( x, y ) = D- y x 2 + y 2 , x x 2 + y 2 E and C is the path in the picture at the top of this page....
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m233_E3sSP10 - Page 1 Math 233 Exam 3 Name: ID: This exam...

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